SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Place the numbers from the least to greatest
![3,6,12,16,30,42,49,50,55,64,67,84,87,89,90](https://img.qammunity.org/2023/formulas/mathematics/college/pv4kjulnx7m7k7o0z3ptfkhb775w1pdna0.png)
STEP 2: Find the median
The median is the number in the middle position. The middle position will be the 8th and the number there is 50.
Median is 50
STEP 3: Find the lower quartile
The lower quartile is the median of the data set to the left of the median
![\begin{gathered} The\text{ data are:} \\ (3,6,12,16,30,42,49) \\ median=16 \\ Q1=16 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/upxfv86vnh1j73ptryjghvsolyysqd0uol.png)
16 is the lower quartile
STEP 4: Find the upper quartile
The upper quartile is the median of the data set to the right of the median
![\begin{gathered} (55,64,67,84,87,89,90) \\ median=84 \\ Q3=84 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1lyhsichrk5echukrzrews9z5cqi73fe45.png)
84 is the upper quartile
STEP 5: Find the maximum and minimum of the data
![\begin{gathered} Minimum=3 \\ Maximum=90 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5xgrgr2y7cbagz215xrn4e9waeydr6fhak.png)
STEP 6: Find the Interquartile range
![Q3-Q1=84-16=68](https://img.qammunity.org/2023/formulas/mathematics/college/ksy7lizxieudk6wzhwl1m6afw81lhvpzg6.png)
Hence, the 5-number summary is given as:
Minimum = 3
Lower quartile = 16
Median = 50
Upper quartile = 84
Maximum = 90