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2x + 5y = 10; (1, 2), (6, 1)is each ordered pair a solution of the inequality

User RunarM
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The equation is:


2x+5y=10

So we try for the coordinate (1,2) so:


\begin{gathered} 2(1)+5(2)=10 \\ 2+10=10 \\ 12\\e10 \end{gathered}

So this is not an ordered pair

For (6,1)


\begin{gathered} 2(6)+5(1)=10 \\ 12+5=10 \\ 17\\e10 \end{gathered}

So non of them is an ordered pair

User Elyptikus
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