51.5k views
4 votes
A child on a swing has a speed of 3.5 m/s

A child on a swing has a speed of 3.5 m/s-example-1
User Bendlas
by
3.7k points

1 Answer

4 votes
Answer:

The height of the swing at the high point = 0.625 m

Step-by-step explanation:

The speed of the child at the low point, v = 3.5 m/s

Let the mass of the boy be represented by m

Let the height of the swing be represented by h

Acceleration due to gravity, g = 9.8 m/s²

At the low point, the child will have a maximum Kinetic Energy but 0 Potential Energy

At the hight point, the child will have the maximum Potential Energy but 0 Kinetic Energy

Kinetic Energy = 0.5mv²

Potential Energy = mgh

Energy is conserved in the system

Kinetic Energy = Potential Energy

0.5mv² = mgh

Divide both sides by m

0.5v² = gh

0.5(3.5²) = 9.8h

6.125 = 9.8h

h = 6.125/9.8

h = 0.625m

The height of the swing at the high point = 0.625 m

User Kinghomer
by
4.3k points