Question

how many grams of no are required to produce 145 g of n2 in the following reaction? 4nh3(g) 6no(g) → 5n2(g) 6h2o(l)

Answer 1

186.357 grams

Step-by-step explanation:

Convert grams of
`N_(2)` to moles:

145g
`N_(2)` x ( 1 mole
`N_(2)` ÷ 28.02 g
`N_(2)` ) = 5.174 moles
`N_(2)`

multiply the mole ration of NO by
`N_(2)` :

5.174 moles
`N_(2)` x ( 6 moles NO ÷ 5 moles
`N_(2)` ) = 6.209 moles NO

now convert moles to grams:

6.209 moles NO x ( 30.01g NO ÷ 1 mole NO) = 186.357 grams NO

molar mass of
`N_(2)` is 28.02g/mole

molar mass of NO is 30.01g/mole