70.3k views
1 vote
X^2+y-9=0 test for symmetry

User Brookie
by
8.6k points

1 Answer

5 votes

We have three tests of symmetry. In respect to the y-axis or in respect to the x-axis, or in respect to the origin.

For symmetry with respect to the Y-Axis, check to see if the equation is the same when we replace x with −x:


x^2+y-9=(-x)^2+y-9=0

Since the equation remains the same when we change the sign of the x variable, the equation is symmetric in respect to the y-axis.

For symmetry with respect to the X-Axis, check to see if the equation is the same when we replace y with −y:


x^2+y-9\\e x^2+(-y)-9=x^2-y-9

Since the equation does not remains the same when we change the sign of the y variable, the equation is not symmetric in respect to the x-axis.

The equation is symmetric with respect to the origin if for every point (x,y) that satisfies the equation, the point (-x, -y) also satisfies the equation.


(-x)^2+(-y)-9=x^2-y-9\\e x^2+y-9

Since it doesn't satisfies this condition, the equation is not symmetric with respect to the origin.

User Xpepermint
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories