Question

5) At a local diner, each hamburger has 50 more calories than each order of fries. If two hamburgers and three orders of fries have a total of 1700 calories, how many calories does one hamburger have?

Answer 1

Each hamburguer has 50 more calories than each order of fries.

We can write this as:

`H=F+50`

being H: calories of the hamburguer, F: calories of the fries.

Two hamburguers and three order of fries have a total of 1700 calories. We can write this as:

`2H+3F=1700`

As we need to solve this for H, we clear F from the first equation, and replace it in the second equation, and solve for H:

`F=H-50`
`\begin{gathered} 2H+3F=2H+3(H-50)=1700 \\ 2H+3H-3\cdot50=1700 \\ 5H-150=1700 \\ 5H=1700+150 \\ 5H=1850 \\ H=(1850)/(5) \\ H=370 \end{gathered}`

The hamburguer has 370 calories.