What is the solution for x^0.5logx=0.01x^2 ?

Erikcw asked Nov 17, 2022

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Erikcw asked Nov 17, 2022

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12 votes

Answer:

x1= 100 x2=99.999

Explanation:

$x^{0.5\log _(10)\left(x\right)}=0.01x^2$

$0.5\log _(10)\left(x\right)\log _(10)\left(x\right)=\log _(10)\left(0.01\right)+2\log _(10)\left(x\right)$

u=log(x)

$0.5uu=\log _(10)\left(0.01\right)+2u$

$u=2+√(1.0E-15),\:u=2-√(1.0E-15)$

$x=10^(2+√(1.0E-15)),\:x=10^(2-√(1.0E-15))$

Ikostia answered Nov 23, 2022

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