For two numbers to be proportional, they must verify:
![y=kx](https://img.qammunity.org/2023/formulas/mathematics/college/zfnjlk9kn7jg7cyy0nlnepmsiaxj3b2oge.png)
"y is proportional to x"
In this case, to verify this, we nedd to calculate if each value of y can be founded by multiplying x by a constant k.
If y = kx is true, then:
![k=(y)/(x)](https://img.qammunity.org/2023/formulas/mathematics/college/wv14j43itnsadhncorbnwrfk6wu4fu47he.png)
And if k is the same for al pairs (x, y) then the relationship is proportional.
Using the table we do:
![\begin{gathered} k=(2)/(12)=(1)/(6) \\ k=(3)/(18)=(1)/(6) \\ k=(4)/(24)=(1)/(6) \\ k=(5)/(30)=(1)/(6) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/92zxaui1xotui5s1xv0iydlfggcjl431pn.png)
Since k is the same for all pair of values, y is proportional to x.
Also we have already calculated k = 1/6
And the equation that represents the table is:
![y=(1)/(6)\cdot x](https://img.qammunity.org/2023/formulas/mathematics/college/1py4yq6wt5b6ort62agd32echuyiqsuesc.png)