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If a sample of N2, at a volume of 40mL is heated from 20°C to 40°C what is the new volume??

User Stryker
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1 Answer

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Answer:Ne Volume = 80mL.

Explanations

GIVEN :

• Volume (V1) = 40ml

,

• Temperature (T1)= 20° C

,

• Temperature (T2) = 40°C

,

• Volume (V2) = ?

We will apply Charles law formula : that states that volume is directly proportional to its absolute temperature, if the pressure remains constant


(V_1)/(T_1)=\text{ }(V_2)/(T_2)

Substituting the given parameters into the above formula, we get that V2 =


\begin{gathered} V_2=\frac{V_1*\text{ T}_2}{T_1} \\ \text{ =}\frac{40\text{ mL * 40 }\degree C}{20\degree C\text{ }} \\ \therefore V_2=\text{ 80 mL } \end{gathered}

Therefore , the new volume = 80mL

User Ken De Guzman
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