Question

Solve the system of equations:y=x+8x+y = 2

Answer 1

i got x=-3 y=5 but i’m not fully sure if it’s correct

Answer 2

We can solve the system of equations:

`\begin{gathered} y=x+8 \\ x+y=2 \end{gathered}`

by elimination method.

If we multiply the first equation by -1, we have the following equivalent system:

`\begin{gathered} -y=-x-8 \\ x+y=2 \end{gathered}`

If we add both equation, we obtain

`x=-x-8+2`

because -y+y=0. Since -8+2=-6, we have

`x=-x-6`

Now, we must move -x to the left hand side as +x. It yields,

`\begin{gathered} x+x=-6 \\ 2x=-6 \\ x=(-6)/(2) \\ x=-3 \end{gathered}`

Now, we can substitute this value into the first equation. It gives

`\begin{gathered} y=-3+8 \\ y=5 \end{gathered}`

Then, the answer is x=-3 and y=5.