Question

A box contains 4 green pebbles and 4 yellow pebbles. What isthe probability of drawing 2 green pebbles and 2 yellowpebbles without replacement?

Answer 1

- The solution steps are given below:

`\begin{gathered} \text{ Number of green pebbles }=4 \\ \text{ Number of yellow pebbles}=4 \\ P(green)=(2)/(4)=(1)/(2) \\ \\ P(yellow)=(2)/(4)=(1)/(2) \\ \\ \text{ The probability of drawing 2 green pebbles and 2 yellow pebbles is:} \\ P(2green,\text{ }2yellow)=(1)/(2)*(1)/(2)=(1)/(4) \end{gathered}`

Final Answer

The answer is:

`(1)/(4)`