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27 A paper airplane was thrown from the top of a tall building. The height of the paper airplane above the ground can be found using the function y = -1.5x + 60, where x is the time in seconds the airplane has been in the air. How many seconds did it take the paper airplane to reach the ground?

User Nokturnal
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7 votes

Answer:

40 seconds

Step-by-step explanation:

To graph the equation y = -1.5x + 60, we need to identify 2 points. So, we will give value to x and then calculate the value for y:

If x = 0, then:

y = -1.5x + 60

y = -1.5(0) + 60

y = 60

If x = 10, then:

y = -1.5(10) + 60

y = -15 + 60

y = 45

So, using the points (0, 60) and (10, 45), we get that the graph for the function is:

Then, the airplane reaches the ground when the height is 0. So, the number of seconds to reach the ground is 40 seconds because when x = 40, y = 0.

Therefore, the answer is 40 seconds.

27 A paper airplane was thrown from the top of a tall building. The height of the-example-1
User Impredicative
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