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Find all the zeroes of each function y=x^3-4x^2+9x-36

User Brendo
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1 Answer

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Given data:

The given expression is y=x^3-4x^2+9x-36.

Substitute 0 for y in the given expression.


\begin{gathered} 0=x^3-4x^2+9x-36 \\ 0=x^2(x-4)+9(x-4) \\ 0=(x-4)(x^2+9) \\ 0=(x-4)(x+3i)(x-3i) \\ x=4,\text{ -3i, +3i} \end{gathered}

Thus, the value of x is 4, -3i, and +3i.

User Jeto
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