Question

Under the Big Top elephant. Ella [2500 kg]. is attracted to Phant, the 3,000 kg elephant. They are separated by 8 m. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)​​

Answer 1

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Here we've been given,

• Universal gravitational constant (G) =
  `\sf{6.67 * {10}^( - 11) }`

• Mass of object 1 (m1) = 2500 kg

• Mass of object 2 (m2) = 3000 kg

• Distance between two objects (r) = 8 m

We have to find the gravitational attraction force (Fg) = ?

The standard formula to solve is given by,

`:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^(2) } }`

`:\implies\tt{F_g = 6.67 * {10}^( - 11) * \frac{(2500 )(3000)}{ {8}^(2) } }`

`:\implies\tt{F_g = 6.67 * {10}^( - 11) * (7500000)/(64) }`

`:\implies\tt{F_g = 7.814 * {10}^( - 6) }`

• Gravitational force of attraction is 7.814 × 10^-6 N.

Answer 2

Hi there!

We can use the same equation for Gravitational Force:

`\large\boxed{F_g = G(m_1m_2)/(r^2)}`

Fg = force due to gravity (N)

G = gravitational constant

m1,m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the values provided:

`F_g = (6.67*10^(-11))((2500)(3000))/(8^2) = \large\boxed{7.814 * 10^(-6)N }`