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1 Write the equation of the line parallel to y = --* - 3 that passes through the point (5,2) 2

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Assuming that the given line is:


y=-3

By comparing with the standard equation of a line with slope m and y-intercept equal to b:


y=mx+b

We can see that the slope is equal to 0, and the y-intercept is equal to -3.

A line parallel to y=-3 will also have a slope equal to 0.

If the point (5,2) is in the line, then the line that we are searching for has a y-intercept of 2:


y=2

Observe that when x=5, y=2. So, the point (5,2) is that line.

Therefore, the equation of the line parallel to y=-3 that passes through the point (5,2), is:


y=2

User Dardarlt
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