Question

What is the speed of the rock in mph after 6 seconds of its drop , the speed of rock in MPH.

Answer 1

Given data

*The value of the acceleration due to gravity is a = 10 m/s^2

*The given time is t = 6 s

*The initial speed of the rock is u = 0 m/s

The relation for the velocity, acceleration, and time is given by the kinematic equation of motion as

`v=u+at`

Substitute the known values in the above expression as

`\begin{gathered} v=0+(10)(6)_{} \\ =60\text{ m/s} \end{gathered}`

The speed of the rock in MPH is converted as

`\begin{gathered} v=(60\text{ m/s) *}\frac{2.2369\text{ mph}}{1(m)/(s)} \\ =134.21\text{ mph} \end{gathered}`

Hence, the speed of the rock is v = 134.21 mph