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give an example of a rational function that has a horizontal asymptote of y=1/2 and vertical asymptote at x=-3

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The horizontal asymptote of a function is the value of y when x -> ∞


\lim _(x\to\infty)f(x)=y

and the vertical asymptote of a function is the x-value when y -> ∞.

For a rational function, the y approaches infinity when the denominator vanishes. In other words, when in q/p, p --> 0.

Using this fact we see that the denominator of our function must vanish at x = -3. This happens when the denominator has the form


(1)/(x+3)

because


\lim _(x\to-3)(1)/(x+3)=\infty

is the vertical asymptote.

For the horizontal asymptote, the function can be of the form


f(x)=(x)/(2(x+3))

because


\textcolor{#FF7968}{\lim _(x\to\infty)(x)/(2(x+3))=(1)/(2)}

Hence the function is


f(x)=(x)/(2(x+3))

User JacobN
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