Question

Yea thanks for all my prayers I appreciate your understanding I will

Answer 1

Given

`h(t)=10+50t+(1)/(2)at^2`

h'(1.25)=9.75 ft/sec

Find

The value of a

Step-by-step explanation

as we have given h'(1.25)=9.75 ft/sec

so , we need to find the first derivative.

`\begin{gathered} h(t)=10+50t+(1)/(2)at^2 \\ \\ h^(\prime)(t)=50+(1)/(2)(2at) \\ h^(\prime)(t)=50+at \end{gathered}`

now substitute the values ,

`\begin{gathered} h^(\prime)(1.25)=50+a(1.25) \\ 9.75=50+a(1.25) \\ \\ -(40.25)/(1.25)=a \\ \\ -32.2=a \end{gathered}`

Final Answer

Therefore, the value of a is -32.2 ft/sec^2