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The volume of the bowling ball , to the nearest tenth, is?The diameter is 8.6 inches

The volume of the bowling ball , to the nearest tenth, is?The diameter is 8.6 inches-example-1

1 Answer

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\text{Volume}=333\text{ cubic inches}

Explanation

we need to asume the bowling ball is a perfect sphere ( with no holes), and we can use the formula for the volume of a sphere


\text{Volume}=(4)/(3)\pi\cdot radius^3

Step 1

Let

diameter=8.6 inches

diameter= 2*radius

hence

radius=8.6 inches /2

radius=4.3 inches

Now, replace


\begin{gathered} \text{Volume}=(4)/(3)\pi\cdot radius^3 \\ \text{Volume}=(4)/(3)\pi\cdot(4.3inches)^3 \\ \text{Volume}=(4)/(3)\pi\cdot79.507in^3 \\ \text{Volume}=333.038\text{ cubic inches} \\ \text{rounded} \\ \text{Volume}=333\text{ cubic inches} \end{gathered}

I hope this helps you

User Zaxonov
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