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What is the relationship between the ratios of sin x° and cos y°?

What is the relationship between the ratios of sin x° and cos y°?-example-1
User Najeira
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1 Answer

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Solution:

Given the right triangle;


\begin{gathered} \sin\theta=(opposite)/(hypotenuse),\cos\theta=(adjacent)/(hypotenuse) \\ \end{gathered}

Thus;


\sin x=(6)/(10),\cos y=(6)/(10)

ANSWER: The ratios are both identical

What is the relationship between the ratios of sin x° and cos y°?-example-1
User Touv
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