What is the relationship between the ratios of sin x° and cos y°?

asked Dec 2, 2023 130k views

4 votes

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2 votes

Solution:

Given the right triangle;

$\begin{gathered} \sin\theta=(opposite)/(hypotenuse),\cos\theta=(adjacent)/(hypotenuse) \\ \end{gathered}$

Thus;

$\sin x=(6)/(10),\cos y=(6)/(10)$

ANSWER: The ratios are both identical

Touv answered Dec 6, 2023

by Touv

8.5k points

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