Question

120 volts is run through a primary coil containing 200 turns. If the secondary coil has 610 turns, what will the new output voltage be?

Answer 1

We are asked to determine the output voltage of a coil with 610 turns given the number of turns and the voltage of the primary coil. To do that we will use the following formula:

`(V_2)/(V_1)=(n_2)/(n_1)`

Where:

`\begin{gathered} n_1,n_2=\text{ number of turns of the primary and secondary coil} \\ V_1,V_2=\text{ voltage of the primary and secondary coil. } \end{gathered}`

Now, we solve for V2 by multiplying both sides by V1:

`V_2=(n_2)/(n_1)V_1`

Now, we substitute the values:

`V_2=(610)/(200)(120V)`

Solving the operations:

`V_2=366V`

Therefore, the voltage of the secondary coil is 366V.