Question

How to solve 3[x+1]>-6 writing it in interval notations?

Answer 1

`3(x+1)>-6`

first solve for x

`\begin{gathered} x+1>-(6)/(3) \\ \\ x+1>-2 \\ x>-2-1 \\ x>-3 \end{gathered}`

This tells us that the values ​​that x can take must be greater than -3

so the interval notation is

`(-3,\infty)`

because these numbers are greater than -3 not including it