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How to solve 3[x+1]>-6 writing it in interval notations?

User Mhawksey
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4 votes

3(x+1)>-6

first solve for x


\begin{gathered} x+1>-(6)/(3) \\ \\ x+1>-2 \\ x>-2-1 \\ x>-3 \end{gathered}

This tells us that the values ​​that x can take must be greater than -3

so the interval notation is


(-3,\infty)

because these numbers are greater than -3 not including it

User Koogunmo
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