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Hi there..I’m stuck on a question and need help.Your class rank in 2018 was 145 out of 435 students. In 2019 your class rant was 160 out of 404 students. A. In which year did you have the higher percentile ranking?B. If you had the data on the cumulative GPA of each student at the end of the spring semester in 2018, what would the mean and the median each tell you and how would you compute each measure?

User Zachery
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Solution

We are given two ranks

First, in 2018, rank of 145 out of 435 students

Secondly, in 2019, rank of 160 out of 404 students.

(A) In which year did you have the higher percentile ranking?

To answer this, we need to calculate the percentiles for the two rankings and comapre them


\begin{gathered} \text{ For year 2018,} \\ \text{The percentile =}(145)/(435)\text{ x 100} \\ =33.33\text{ \%} \end{gathered}
\begin{gathered} \text{ For year 2019,} \\ \text{The percentile = }(160)/(404)\text{ x 100} \\ =\text{ 39.604 \%} \end{gathered}

By comapring the percentile ranking, we realize that year 2019 has higher percentile (39.6%) comapred to year 2018 (33.33%)

(B)

If you had the data on the cumulative GPA of each student at the end of the spring semester in 2018, what would the mean and the median each tell you and how would you compute each measure?

The mean and the median tells us about the measure of the center of the dataset

To compute the mean, we us the formula


\begin{gathered} \operatorname{mean}\text{ =}\frac{\text{ sum of terms }}{\text{ number of terms }} \\ \\ \text{Median = data at the midlle after re-arranging in either ascending or descending oder} \end{gathered}

User Gil Kr
by
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