Question

Y=-x^2+12x-4Complete the square for - x^2+12x-4Use ax^2+bx+cA=-1, b=12, c=-4

Answer 1

The given equation is

`y=-x^2+12x-4`

To complete the square take -1 as a common factor from the right side

`-x^2+12x-4=-1(x^2-12x+4)`

Divide the term of x by 2 to find the product of the first and second terms in the bracket

`(-12x)/(2)=-6x`

The bracket will be (x - 6)

Square it

`(x-6)^2=x^2-12x+36`

Then add and subtract (36 - 4)

`-\lbrack(x^2-12x+4+32)-32\rbrack=-(x^2-12x+36)+32`

Make the trinomial a square binomial

`-(x^2-12x+36)-32=-(x-6)^2+32`

The completing square is

`-x^2+12x-4=-(x-6)^2+32`