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What volume of a 3.00M Kl stock solution would you use to make 0.300 L of a 1.25M Kl solution?

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Please, look at the next drawing:

According to this drawing, we want to find out V1:

Let's use this formula: M1 x V1 = M2 x V2

Clear V1: V1 = M2 x V2/M1 = 1.25 M x 0.300 L/3.00 M = 0.125 L (0.125 L must be taken from solution 1)

Answer: V1 = 0.125 L

What volume of a 3.00M Kl stock solution would you use to make 0.300 L of a 1.25M-example-1
User JGeerWM
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