Question

Hi! I got the answer but I just need to find how to solve it.

Answer 1

(1/36)^x-3 = 216^ (2x + 2)

Apply

1/36 = 1/6^2

216 = 6^3

Then, now us a^b^c = a^(b•c)

(1/6^2)^ -3 = ?

. = (1/6)^2•-3 = (1/6)^-6

. = 1/(1/6^6)

Here apply (1/1/A = A)

. = 6^6 = 46656

Now find

216^ (0+2) = (6^3)^2

. = 6^(3•2)

. = 6^6

. = 46656

Then in this way its demostrated that x= 0 is solution

OPTION B) {0}