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SOLVE: 2M + 12 = 3 M - 31+

User Langston
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2M + 12 = 3M - 31

Solving for M:


\begin{gathered} 2M+12=3M-31 \\ \text{Subtract 2M from both sides:} \\ 2M+12-2M=3M-31-2M \\ 12=M-31 \\ \text{Add 31 to both sides:} \\ 12+31=M-31+31 \\ 43=M \end{gathered}

2m+12=3m-31------------------------------->given

12 = m -31----------------------------------->Subtraction POC

43 = m ---------------------------------------> addition POC

m = 43--------------------------------------> symmetric POC

User Hadi Samadzad
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