What is the solution set for -4 x - 10 ≤ 2?

asked Nov 12, 2023 70.8k views

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6 votes

$-4x-10\le2$

Adding 10 to both sides.

$\begin{gathered} -4x-10+10\le2+10 \\ -4x\le12 \\ \text{ Dividing both sides by -4, we have} \\ (-4x)/(-4)\ge(12)/(-4) \\ x\ge-3 \end{gathered}$

So the solution set is the set

$\mleft\lbrace x\in\mathfrak{\Re }\colon x\ge-3\mright\rbrace$

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