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Nell's kite has a 350-foot string. When it is completely out. Lan measures the angle to be47.5". How far does Lan need to walk to be directly under the kite?

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Answer:

Step-by-step explanation:

Let the scenario be shown in the diagram below

We need to find x as follows


\begin{gathered} \cos 47.5=(x)/(300) \\ \\ x=300\cos 47.5=202.7 \end{gathered}

Lan needs to walk 202.7 fo

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