Question

Write the equation of the line passing through the point (4, -9) with a slope of -2/3. Write the equation

in standard form.

Answer 1

The equation of the line passing through the point (4, -9) with a slope of -2/3 in standard form is 2x + 3y = -19.

Step-by-step explanation:

The question asks for the equation of a line that passes through the point (4, -9) with a slope of -2/3. To find the equation, we can use the point-slope form of a line which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. Substituting the given point and slope, we get:

y - (-9) = -2/3(x - 4)

Simplifying this equation, we subtract -9 from both sides and distribute the slope to get:

y + 9 = -2/3x + 8/3

To write this in standard form, Ax + By = C, we need to get the variables x and y on one side and the constant on the other side. First, multiply everything by 3 to eliminate the fraction:

3y + 27 = -2x + 8

Then move the x-term to the left side:

2x + 3y = -27 + 8

Finally, simplify the right side to get the standard form equation:

2x + 3y = -19

Answer 2

2 x -4 2m + 5m a + b + c

(expresion)

4n + 7 = 11 b - 2 = 3 x + y + z = 187

twice a number increased by four is 10 the difference of a number and 2 is 5

(equation)