The molarity is defined as:
![Molarity=(MolesSolute)/(LitersSolution)](https://img.qammunity.org/2023/formulas/chemistry/college/9x0y0t94h05obiu5zc5014ynvb7k0r4bpq.png)
We have the molarity (2.8M) and the volume (23mL). We have to take into account that volume must be expressed in liters, so the volume that we will use will be:
![V=23mL*(1L)/(1000mL)=0.023L](https://img.qammunity.org/2023/formulas/chemistry/college/qz30fvawfo9w2hwqhrjv5cq54lz7o5r8c8.png)
So, the moles of solute will be:
![MolesSolute=Molarity* Volume](https://img.qammunity.org/2023/formulas/chemistry/college/pbjpum7js0mu5v31q8gsryi24saa1leobv.png)
![MolesSolute=2.8M*0.023L=0.0644moles](https://img.qammunity.org/2023/formulas/chemistry/college/1bm6358v45ew0lbqz3c3z11dnwvcyxkruo.png)
Answer: There are 0.0644moles