Question

50 N of force is applied to the 6 kg box. If the coefficient of frictionis 0.3, find the friction force.

Answer 1

Given:

The mass of the box is,

`m=6\text{ kg}`

The force applied on the box is,

`F=50\text{ N}`

The angle of the force with the horizontal is,

`\theta=53^(\circ)`

The coefficient of friction is,

`\mu=0.3`

The Normal force on the box is,

`\begin{gathered} N=\text{Fsin}\theta-mg \\ =50*\sin 53^(\circ)-6*9.8 \\ =-18.9\text{ N} \end{gathered}`

The frictional force on the box is (we take the magnitude of the force only)

`\begin{gathered} f=\mu N \\ =0.3*18.9 \\ =5.6\text{ N} \end{gathered}`

Hence the frictional force is 5.6 N.