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a population of a school is 800 and is decreasing at a rate of 2% per year. Write an exponential decay function to model the given situation. Then find the population after 4 years

User MichaC
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Exponential Decay Function

An exponential decaying function is expressed as:


C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

We are given the initial population of a school Po=800. We also know the rate of change is r=2%=0.02 per year.

Substituting the values in the exponential model, using the variable P for the population:


P(t)=800\cdot(1-0.02)^t

Calculating:


P(t)=800\cdot(0.98)^t

This is the required equation for the model.

The population after t=4 years is:


P(4)=800\cdot(0.98)^4

Using a scientific calculator:


\begin{gathered} P(4)=800\cdot0.9224 \\ P(4)\approx738 \end{gathered}

The population after 4 years will be approximately 738

User Kca
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