From the question it is given that the length of the rectangle is 4 less than the three time of the width.
![l=3w-4](https://img.qammunity.org/2023/formulas/mathematics/college/guinybvqp6715sh0a39vile0fj96n8p2ad.png)
Here, 'l' represnts the length and 'w' represents the width.
The area of the rectangle is,
![A=l* w](https://img.qammunity.org/2023/formulas/mathematics/college/lmmzpu3pbc5f31ild3jzkycy7t9l4cj8y8.png)
Substitute expression 'l=3w-4' in the above equation.
![\begin{gathered} A=(3w-4)w \\ A=3w^2-4w \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zu6nqvc7x03e90rg9cgewxg8dn8ug7clcg.png)
Thus, the correct option is option D.