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A card is drawn at random from a standard deck. That card is not put back in the deck, and a second card is drawn at random from the remaining cards in thedeck. Neither of the cards drawn so far are put back in the deck, and a third card is drawn at random from the remaining cards in the deck.What is the probability that the first card drawn is a face card, the second card drawn is a five, and the third card drawn is a five?Do not round your intermediate computations. Round your final answer to four decimal places.

User LorenVS
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1 Answer

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This probability without replacement

Let the probability of first card=P(F)

probability of the second card=P(E)

probability of the third card=P(B)

The total outcome is 52

Total face card =12

The probability of face card is


P(F)=(12)/(52)=0.2308

The probability of picking the second card without replacement is


P(E)=(5)/(51)=0.09804

The Probability of picking the third card is five is

Total number of 5 = 4


P(B)=(4)/(50)=0.08

The probability of the first card, second card, and third card is


\begin{gathered} P(F)* P(E)* P(B) \\ (12)/(52)*(5)/(51)*(4)/(50)=0.001809 \end{gathered}

The probability is 0.0018

User Carmageddon
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