We are given a figure and we are asked to determine its area. To do that we need to add the areas of the square and the semi-circle. The area of the square is the measure of its side squared, that is:
![A_s=l^2](https://img.qammunity.org/2023/formulas/mathematics/college/o0xzghelm7rpypwc205kswg669dkek5jfq.png)
Replacing:
![\begin{gathered} A_{}s=(6in)^2 \\ A_{}s=36in^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/meutfmnk310w39gdau4yhbigv2p9qr79u4.png)
The area of the semi-circle is given by:
![A_(sc)=(\pi r^2)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/2qcghmfp879gfb1iff8e6hswcyzx5jj4ov.png)
Replacing the value of the radius:
![A_(sc)=(\pi(3in)^2)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/yjz7u1v3s05xn04shqg6f3uc31tyhkq6lq.png)
Solving the operations:
![A_(sc)=14.1in^2](https://img.qammunity.org/2023/formulas/mathematics/college/du30uyp1x2pnp4tlt800ppwfhjc71gsa0u.png)
The total area is:
![A=A_s+A_(sc)](https://img.qammunity.org/2023/formulas/mathematics/college/kq5fz66gye3m0cv1hby9dhjsjpbv1g25h5.png)
Replacing:
![\begin{gathered} A=36in^2+14.1in^2 \\ A=50.1in^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/skispifelhvbtmthbiq9ixaajui9adjqsx.png)
Therefore, the area is 50.1 square inches.