Answer:
397 shelter openings are needed
Explanations:
This is a normal distribution
Mean = 250
Standard Deviation = 75
There are not enough beds 95% of the time
Confidence Level = 95/100 = 0.95
Significance Level (SL) = 1 - Confidence Level (CL)
SL = 1 - 0.95
SL = 0.05
Z-score at 0.05 Significance Level = 1.96
z = 1.96
![\begin{gathered} \text{Mean, }\mu\text{ = 250} \\ \text{Standar Deviation, }\delta\text{ = 75} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e70dtokyd15c5abi4vznrjluttgd0ggkh6.png)
Let the number of shelter openings be represented by Y
![\begin{gathered} Y\text{ = }\mu\text{ + z}\delta \\ Y\text{ = }250\text{ + 1.96(75)} \\ Y\text{ = 250 + }147 \\ Y\text{ = }397 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qsnngat9wpa5e3d1dgh0aa8wx0uzoehnyd.png)
397 shelter openings will be needed