Question

Function g defined by g(x)=3-x^2, x ER evaluate:g(-3) and g(1/2)

Answer 1

Given

`g(x)=3-x^2`

To find the values of g(-3) and g(1/2).

Step-by-step explanation:

It is given that,

`g(x)=3-x^2`

Then, for x=-3,

`\begin{gathered} g(-3)=3-(-3)^2 \\ =3-9 \\ =-6 \end{gathered}`

Also, for x=1/2,

`\begin{gathered} g((1)/(2))=3-((1)/(2))^2 \\ =3-(1)/(4) \\ =(12-1)/(4) \\ =(11)/(4) \end{gathered}`

Hence, the answer is -6 and 11/4.