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the first answer choice is 2√6, 3√7, or 6√3the second choice box is 3 and 7, -8.5 and 8.5, or -1 and 1

the first answer choice is 2√6, 3√7, or 6√3the second choice box is 3 and 7, -8.5 and-example-1
User Worp
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In order to prove that the diagonals of a square are congruent, first we need to find their length by using the Pythagorean Theorem:


h^2=a^2+b^2

Where h is the hypotenuse of the triangle (in this case the diagonal), a and b are the sides of the triangle. In the coordinate plane, we can see that each side measures 6 units. By replacing these values we can find the length of LN and KM as follows:


\begin{gathered} \bar{LN}=6^2+6^2 \\ \bar{LN}=36+36 \\ \bar{LN}=72 \\ \bar{LN}=√(72) \\ \bar{LN}=\sqrt[]{36\cdot2} \\ \bar{LN}=\sqrt[]{36}\cdot\sqrt[]{2} \\ \bar{LN}=6\sqrt[]{2} \end{gathered}

Now, for KM:


\begin{gathered} \bar{KM}=6^2+6^2 \\ \bar{KM}=36+36 \\ \bar{KM}=72 \\ \bar{KM}=\sqrt[]{36\cdot2} \\ \bar{KM}=\sqrt[]{36}\cdot\sqrt[]{2} \\ \bar{KM}=6\sqrt[]{2} \end{gathered}

Then, as the diagonals have the same measure they are congruent.

To find the slope, we can use the following formula:


m=(y2-y1)/(x2-x1)

Were (x1,y1) and (x2,y2) are the coordinates of two points on the line.

The coordinates of K, L, M and N are:

K(2,1) and M(8,-5)

L(2,-5) and N(8,1).

The slope of KM is:


m=(-5-1)/(8-2)=(-6)/(6)=-1

And the slope of LN is:


m=(1-(-5))/(8-2)=(1+5)/(6)=(6)/(6)=1

When two lines are perpendicular, the product of their slopes is equal to -1, then if m1

User James Hibbard
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