Fructose contributes with approximately 250 kJ of caloric content for a golden apple.
The first thing we need to do is calculate the molar mass of fructose (C6H12O6), using the following atomic masses:
C: 12 u
H: 1 u
O: 16 u
molar mass = (6 * 12) + (12 * 1) + (6* 16) = 180 g/mol
From the problem, we know that each mol of fructose releases 2812 kJ, and the question is: how much energy does 16g of fructose release? With that in mind, we can write:
180g C6H12O6 ---------- 2812 kJ
16g C6H12O6 ---------- x (kJ)
Solving for x, we have that that fructose contributes with approximately 250 kJ to the caloric content of a golden apple.