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Solve for a.- 4a + 26 ≤ 2Oaz-7O a≥6Oa≥-6○ a ≤ 6

Solve for a.- 4a + 26 ≤ 2Oaz-7O a≥6Oa≥-6○ a ≤ 6-example-1

1 Answer

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Given the inequality:


-4a+26\leq2

You can solve for "a" as follows:

1. Apply the Subtraction Property of Inequality by subtracting 26 from both sides of the inequality:


-4a+26-(26)\leq2-(26)


-4a\leq-24

2. Apply the Division Property of Inequality by dividing both sides by -4. As you are dividing both sides by a negative number, the direction of the inequality symbol changes:


\begin{gathered} (-4a)/(-4)\ge(-24)/(-4) \\ \\ a\ge6 \end{gathered}

Hence, the answer is: Second option.

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