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2 = logae. I need help please

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Hello there. To solve this question, we'll have to remember some properties about logarithms.

Given the logarithmic equation:


2=\log _ae

We have to determine the base a.

For this, remember that the logarithmic function is defined as


\log _ab

For values of a, b such that


\begin{gathered} 00 \end{gathered}

Also, we need the following property:


\log _ab=c\leftrightarrows b=a^c

Such that we have:


\begin{gathered} 2=\log _ae \\ \Rightarrow e=a^2 \end{gathered}

Take the square root on both sides of the equation


\begin{gathered} \sqrt[]{e}=\sqrt[]{a^2} \\ |a|=\sqrt[]{e} \end{gathered}

This gives us two solutions, according to the definition of the absolute value function:


|x|=\begin{cases}x,\text{ if x is greater than or equal to zero} \\ -x,\text{ if x is less than zero}\end{cases}

In this case, remember that a > 0, so the only solution we're interested is:


a=\sqrt[]{e}

In this case, we've showed that:


\log _{\sqrt[]{e}}e=2

In fact, all the other properties hold and this is the solution for the base a in this logarithmic equation.

User Julisa
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