Question

In a class of students, the following data table summarizes how many students have acat or a dog. What is the probability that a student has a dog given that they do nothave a cat?Has a cat Does not have a cat39Has a dogDoes not have a dog213Answer:Submit Answer

Answer 1

`(1)/(3)`

Step-by-step explanation

Probability is simply how likely something is to happen. Probability of event to happen P(E) = Number of favourable outcomes/Total Number of outcomes.

`P=\frac{favorable\text{ outcomes}}{\text{total outcomes}}`

so

Step 1

Let

Number of studenst tha have a dog, given the do ot have a cat

=9

so

`\text{Favorable ourcomes=9}`

and

total students = 3+9+2+13=27

so

`\text{total outcomes = 27}`

finally, replace

`\begin{gathered} P=\frac{favorable\text{ outcomes}}{\text{total outcomes}} \\ P=(9)/(27) \\ P=(1)/(3) \end{gathered}`

therefore, the answer is

`(1)/(3)`

I hope this helps you