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Find the missing side or angle.Round to the nearest tenth.A=60°b=50C=48a=[ ? ]

Find the missing side or angle.Round to the nearest tenth.A=60°b=50C=48a=[ ? ]-example-1
User Yahia
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1 Answer

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Using this drawing as a guide, the problem becomes easier to tackle. In every triangle, the sum of all 3 angles must be equal to 180 degrees. You have no way of knowing the angle that would be B, so a good strategy is to cut a line just below the angle C so you get 2 right triangles.

Then, using the sine law, you can use that sin(A)=a'/b, where a' is not a but the right side of the new triangle.

By using the previous formula, you get that b*sin(A)=a'=50*sin(60 degrees)=43.3. You also have that cos(A)=(c-x)/b so -cos(A)*b +c=x


x=-\cos (60^(\circ))\cdot50\text{ +48 =}23

So, with a' and x, you can apply the Pythagorean theorem to find a.


a^(\prime2)+x^2=a^2\rightarrow a=\sqrt[]{23^2+43.3^2}=49.0

This is the length a, which is the final answer.

Find the missing side or angle.Round to the nearest tenth.A=60°b=50C=48a=[ ? ]-example-1
User NickMcB
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