Question

If abcd is dilated by a factor of 1/2 the coordinate of d' would be

Answer 1

The co ordinate of the original coordinate of D is,

`D(2,-2)`

So, the coordinate of the D' will get by multiplying the coordinate by 1/2

`D^(\prime)((2)/(2),-(2)/(2))=D^(\prime)(1,-1)`

So, the coordinate of D' is,

`D^(\prime)(1,-1)`