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Hello! I need some help with this homework question posted below. Q16

Hello! I need some help with this homework question posted below. Q16-example-1

1 Answer

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Given the function


f(x)=-2x^2+2x-1

Graphing

a) According to the graph:

The graph of f opens down

The vertex of f is (0.5, -0.5)

The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola. In this case, the vertex of the parabola is (0.5, -0.5). Therefore:

The axis of symmetry is x = 0.5

The y-intercept of a graph is the point where the graph crosses the y-axis. So,

Answer: A. The y-intercept is -1

The x-intercept of a graph is the point where the graph crosses the x-axis. In this case, we see that the graph does not cross the x-axis, so there is no x-intercept.

Answer: B. There is no x-intercept

b) The domain is the values of x. The range is the y values. Therefore:

The domain of f is (-∞, ∞)

The range of f is (-∞, -0.5]

c) -A function is increasing when as the value of the independent variable increases, the value of the function increases.

-A function is decreasing when, as the value of the independent variable increases, the value of the function decreases. So:

The function is increasing on the interval (-∞, 0.5)

The function is decreasing on the interval (0.5, ∞)

(1) down

Hello! I need some help with this homework question posted below. Q16-example-1
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