Question

Find the water pressure at ground level to supply water to the third floor of a building that is 12.00 m off the ground, with a pressure of 330 kPa

Answer 1

Given data:

The height of the building is h=12 m.

The pressure on the ground is

`P_G=330\text{ kPa}`

The water pressure at the ground level can be given as,

`P_T=p_G+\rho gh`

Here,

`\rho`

is the density of water whose value is

`1000kg/m^3`

and g is the gravity whose value is

`9.81m/s^2`

Substituting the values in the above equation, we get:

`\begin{gathered} P_T=330\text{ kPa}(\frac{1000N/m^2}{1\text{ kPa}})+1000kg/m^3*9.81m/s^2*12m((1N/m^2)/(1kg/ms^2)) \\ =447720N/m^2(\frac{1\text{ Pa}}{1N/m^2})(\frac{1\text{ kPa}}{1000\text{ Pa}}) \\ =447.72\text{ kPa} \end{gathered}`

Thus, the water pressure at the ground level is 447.72 kPa.