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The figure below is a net for a triangular prism.What is the surface area of the triangular prism, in square inches

The figure below is a net for a triangular prism.What is the surface area of the triangular-example-1
User Thdox
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We have to find the areas of all figures and then add them.

First rectangle:

A = b*h (b=base, h=height)

A = (15)*(7) in^2 (Replacing the values)

A= 105 in^2 (Multiplying)

Second rectangle:

A = b*h (b=base, h=height)

A = (15)*(9) in^2 (Replacing the values)

A= 135 in^2 (Multiplying)

Third rectangle:

A = b*h (b=base, h=height)

A = (15)*(11.4) in^2 (Replacing the values)

A= 171 in^2 (Multiplying)

Area of both triangles:

A=2*b*h/2 (b=base, h=height)

A=b*h (Simplifying)

A=(9)*(7)in^2 (Replacing the values)

A=63 in^2 (Multiplying)

Adding all areas, we have:

105 in^2 + 135 in^2 + 171 in^2 + 63 in^2 = 474 in^2

The answer is 474 in^2

User Peernohell
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